CSIR NET June 2024: The National Testing Agency (NTA) released a new notification for the Joint CSIR UGC National Eligibility Test (NET) June 2024 Notification. Eligible candidates can apply online from 1st May 2024; the last date for application form submission is 21st May 2024. Both Males and Females can apply online for CSIR-UGC NET June 2024 through the official website of the CSIR NET. You can also download the CSIR NET June 2024 Application Form Notification PDF from the link given below.
CSIR NET June 2024 Notification Highlights
Recruitment Organization | National Testing Agency (NTA) |
Exam Name | CSIR National Eligibility Test (NET) |
Category | Latest Jobs |
Job Location | All India |
Last date for Apply | 21.05.2024 |
Official Website | CSIR NET |
Join Us on Telegram | Join Now |
Best Books for Joint CSIR UGC NET Exam June 2024
CSIR NET June 2024 Notification PDF
Download the CSIR NET June 2024 Notification PDF for different posts from the direct link provided below:
CSIR NET June 2024 Notification PDF | Download |
CSIR NET Notification June 2024 Important Dates
CSIR NET Recruitment 2024 Notification Out | 01 May 2024 |
CSIR NET Application Form 2024 Apply Online Start | 01 May 2024 |
CSIR NET Application Form 2024 Last Date to Apply | 21 May 2024 |
CSIR NET Education Qualification 2024
Candidates must confirm they fulfill all the qualifying criteria before applying. However, the board has mentioned the requirements for eligibility conditions as given below:
Exam Name | Education Qualification |
CSIR NET JUNE 2024 | Master’s Degree |
CSIR NET Age Limit June 2024
- JRF: Not more than 30 years For JRF.
- Assistant Professor: No upper age limit.
- Admission to PhD: No upper age limit for admission to PhD.
CSIR NET Selection Procedure 2024
For clearing the CSIR NET June 2024 exam, the following is the selection process:
Papers | Questions/No. Of Question to attempt/Marks |
---|---|
CHEMICAL SCIENCES (701) | 120/75/200 |
EARTH, ATMOSPHERIC, OCEAN AND PLANETARY SCIENCES (702) | 150/75/200 |
LIFE SCIENCES (703) | 145/75/200 |
MATHEMATICAL SCIENCES (704) | 120/60/200 |
PHYSICAL SCIENCES (705) | 75/55/200 |
How to apply for CSIR NET June 2024 Application Form
- First, read the Official Notification carefully.
- Click on the link to apply online.
- Click on the link “Apply Online” on the Home Page.
- Register yourself by clicking on “New Registration” if not registered already.
- After registering, or if already registered, the candidate must log in to his or her account on the OTR page. Once logged in, the candidate will see a list of live advertisements on the dashboard. The candidate will only apply for a specific position through this portal. The candidate’s application will be submitted only after uploading the required papers as specified in the advertisement.
- Pay the required fees.
- Take the printout of the application form for future reference.
CSIR NET JUNE 2024 Application Fees
UR | Rs. 1150/- |
EWS/OBC | Rs. 600/- |
All other | Rs. 325/- |
Mode of Payment | Online |
CSIR NET June 2024 Important Links
CSIR NET June 2024 Notification PDF | Download PDF |
CSIR NET Exam 2024 Apply Online | Apply Online |
CSIR NET Notification 2024 Details | Watch Video in Hindi |
CSIR NET Official Website | Official Website |
Check Other Govt. Jobs | Trending Rojgar |
Latest Updates On Telegram | Join Now |
Frequently Asked Questions (FAQs)
Question 1: How can I download the CSIR NET June 2024 Notification PDF?
Answer: You can download the official notification from the Official website.
Question 2: What is the Qualification for CSIR NET JUNE 2024?
Answer: Check in the article.
Question 3: What are the CSIR NET June 2024 Exam age criteria?
Answer:
- JRF: Not more than 30 years For JRF.
- Assistant Professor: No upper age limit.
- Admission to PhD: No upper age limit for admission to PhD.
Question 4: How can I apply for CSIR NET June 2024?
Answer: Candidates can apply Online by filling out the application form on the official website.
Question 5: What is the website link to complete CSIR NET Application Form 2024?
Answer: Click to apply online.